In the adjoining figure, O is the centre of the centre of the circle. If diameter AC=26cm and chord AB=10cm, then find the distances of the chord AB from the centre of the circle.

In the adjoining figure, O is the centre of the centre of the circle.

1.	In the adjoining figure, O is the centre of the centre of the circle. If diameter AC=26cm and chord AB=10cm, then find the distances of the chord AB from the centre of the circle.
Answer» Radius of circle `=("diameter")/(2)` `rArr AO=(26)/(2)=13cm` `AM=(AB)/(2)=(10)/(2)=5cm, (because "perpendicular drawn from centre to the chrod bisects the chord" )` Now, in `Delta AOM`, `AM^2+OM^2=AO^2` `rArrOM^2=AO^2-AM^2=13^2-5^2=169-25=144` `rArrOM=sqrt(144)=12 cm` Therefore, the distance of chord from the centre =12 cm

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In the adjoining figure, O is the centre of the centre of the circle. If diameter AC=26cm and chord AB=10cm, then find the distances of the chord AB from the centre of the circle.

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