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| 1. |
In the adjoining figure, AP and BP are angle bisector of ∠A and ∠B which meet at a point P of the parallelogram ABCD. Then 2∠APB = (A) ∠A + ∠B (B) ∠A + ∠C (C) ∠B + ∠D (D) ∠C + ∠D |
| Answer» The correct option is (D). | |