In the adjoining figure, ABCD is a square and ΔEDC is an equilateral

1.	In the adjoining figure, ABCD is a square and ΔEDC is an equilateral triangle. Prove that (i) AE=BE, (ii) ∠DAE=15∘.
Answer» In the adjoining figure, $A B C D$ is a square and $Δ E D C$ is an equilateral triangle. Prove that (i) $A E = B E,$ (ii) $∠ D A E = 15^{\circ}$ .

In the adjoining figure, ABCD is a square and ΔEDC is an equilateral triangle. Prove that (i) AE=BE, (ii) ∠DAE=15∘.

Answer»

In the adjoining figure, $A B C D$ is a square and $Δ E D C$ is an equilateral triangle. Prove that (i) $A E = B E,$ (ii) $∠ D A E = 15^{\circ}$ .