In the adjoining fegure ap -4 cm,bq-6cm and cr-5cm find perimeter of a

1.	In the adjoining fegure ap -4 cm,bq-6cm and cr-5cm find perimeter of abc
Answer» Answer: The perimeter of ∆ABC is 30 cm Step-by-step explanation: Here, in the above triangle Seg AB is the tangent at point P, Seg AC is the tangent at POINT R and Seg BC is the tangent at point Q Also, BY USING *TANGENT* *SEGMENT* *THEOREM* : *TANGENT SEGMENTS* *DRAWN* *FROM* AN *EXTERNAL* POINT TO A CIRCLE ARE CONGRUENT. :. AP congruent AR :. AP = 4 cm then AR = 4 cm :. BQ congruent BP :. BQ = 6 cm then BP = 6 cm :. RC congruent QC :. RC = 5 cm then QC = 5 cm then, :. AB = AP + BP ---(Points A,P & B are collinear) :. AB = 10 cm :. AC = AR + RC ---(Points A,R & C are collinear) :. AC = 9 cm :. BC = BQ + QC ---(Points B,Q & C are collinear) :. BC = 11 cm :. Perimeter of triangle = AB + BC + AC :. Perimeter of triangle = 10 + 11 + 9 :. Perimeter of triangle = 30 cm HOPE IT HELPS YOU !! MARK ME AS BRAINLIEST** .

In the adjoining fegure ap -4 cm,bq-6cm and cr-5cm find perimeter of abc

Answer»

Answer:

The perimeter of ∆ABC is 30 cm

Step-by-step explanation:

Here, in the above triangle

Seg AB is the tangent at point P,

Seg AC is the tangent at POINT R

and

Seg BC is the tangent at point Q

Also,

BY USING TANGENT SEGMENT THEOREM :

TANGENT SEGMENTS DRAWN FROM AN EXTERNAL POINT TO A CIRCLE ARE CONGRUENT.

:. AP congruent AR

:. AP = 4 cm then AR = 4 cm

:. BQ congruent BP

:. BQ = 6 cm then BP = 6 cm

:. RC congruent QC

:. RC = 5 cm then QC = 5 cm

then,

:. AB = AP + BP ---(Points A,P & B are collinear)

:. AB = 10 cm

:. AC = AR + RC ---(Points A,R & C are collinear)

:. AC = 9 cm

:. BC = BQ + QC ---(Points B,Q & C are collinear)

:. BC = 11 cm

:. Perimeter of triangle = AB + BC + AC

:. Perimeter of triangle = 10 + 11 + 9

:. Perimeter of triangle = 30 cm

HOPE IT HELPS YOU !!

MARK ME AS BRAINLIEST .