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In the adjoining circuit, the e.m.f. of the cell is 2 volt and the internal resistance is negligible. The resistance of the voltmeter is `80 ohm`. The reading of the voltmeter will be A. 0.80 voltB. 1.60 voltC. 1.33 voltD. 2.00 volt |
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Answer» Correct Answer - C (c ) Total resistanceof the circuit `= (80)/(2) + 20 = 60 Omega` `implies` Main current `i= (2)/(60) = (1)/(30) A` Combination of voltmeter and `80 Omega` resistance is connected in series with `20 Omega`, so current through `20 Omega` and this combination will be same `= (1)/(30) A` Since the resistance of voltmeter is also `80 Omega`, so this current is equally distributed in `80 Omega` , so this current is equally distributed in `80 Omega` resistance and voltmeter (i.e., `(1)/(60) A` through each) `P.D.` across `80 Omega` resistance `= (1)/(60) xx 80 = 1.33 V` |
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