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In the adjacent figures, which has the shortest path- A. Fig 1B. Fig 2C. Fig 3D. Fig 4 |
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Answer» Correct Answer - B A (1,1),B(2,3),C(5,2),D(3,0) For Fig 1 `AB=sqrt(1+4)=sqrt5` `BC=sqrt(9+1)=sqrt(10)` `CD=sqrt(4+4)=sqrt(8)` then `AB+BC+CD+=8.22` For Fig 2 `AB=1,BC=2,CD=sqrt(10),DE=sqrt(8)` `AB+BC+CD+DE=8.99` Is max distance For Fig 3 `AB=sqrt(5),BC=2,CD=sqrt(5),DE=sqrt(5)` `AB+BC+CD+DE=8.70` For Fig 4 `AB=1,BC=2,CD=sqrt(13),DE=sqrt(5)` `AB+BC+CD+DE=8.841` |
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