1.

In the adjacent figure, AB is a chord of circle with centre O. CD is the diameter perpendicualr to AB. Show that AD=BD.

Answer»

Hi ,

GIVEN : AB is a chord of a circle with center

O . CD is the diameter Perpendicular to AB.

RTP : AD = BD

proof :

Let P is the intersecting point of AB and CD.

From triangles APD and BPD


DP = DP ( Common side )

AP = PB ( diameter bisects chord )

Therefore ,

TRIANGLE APD congruent to triangle BPD

( SAS creiteria )

AD = BD ( corrospoding parts of congruent

triangles )

Hence proved.

I hope this helps you.

: )


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