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In the above question, the velocity of the image of `Q` in plane mirror of block `P` with respect to ground when `Q` is at the lowest point first time is:A. `sqrt((2mg^(2))/(K))`B. `sqrt((4mg^(2))/(K))`C. `sqrt((3mg^(2))/(K))`D. 0 |
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Answer» Correct Answer - D At `t = (T_(Q))/(2)` both the blocks are at extreme position and their velocity is zero `:. V_(P) = V_(Q) =0` |
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