In the above question, the resultant upward force exerted by the sides of the glass on the water is

In the above question, the resultant upward force exerted by the sides

1.	In the above question, the resultant upward force exerted by the sides of the glass on the water is
Answer» 100 N 102 N 303 N 211 N Solution :Force exerted by atmosphere on WATER is `F_(2)=(P_(a))A_(2)=(1.01xx10^(5))xx(3XX10^(-3)) =303 N` (downwards) Force exerted by bottom on the water, `F_(3)=-F_(1)=102 N` (downwards) Let F be the force exerted by side walls on THWE water (upwards) there EQUILIBRIUM of water : net upward force = net downward force or `F+F_(3)=F_(2)+W` `:.F=F_(2)+W-f_(3)=303+10-102=211 N` (downwards)