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In the above figure , O is the centre of the circle, AB and CD are diameters. `/_ COB =50^(@)=50^(@)` . If E is the midpoint of AF, then find `/_ ADF`A. `130^(@)`B. `100^(@)`C. `110^(@)`D. `120^(@)` |
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Answer» Correct Answer - a `/_ COB= /_ AOD =50^(@)` (Vertically opposite angles ). Since E is the mid-point of AF,`/_ OEA = /_ OEF=90^(@)`. `implies /_OAE =/_OFE =40^(@)` `implies /_DOF =50^(@)` `:. /_ADF =1//2 `( reflex `( /_AOF) =130^(@)` |
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