In the above figure, O is the centre of the circle and `AB=CD`. If `/ – InterviewSolution

1.	In the above figure, O is the centre of the circle and `AB=CD`. If `/_ APB=110^(@)`, then find the angle made by the chord CD at the centre.A. `220^(@)`B. `110^(@)`C. `120^(@)`D. `140^(@)`
Answer» Correct Answer - d (i) Equal chords subtend equal angles at the centre. (ii) JoinAO, OC, OB and OD. (iii) Reflex `/_ AOB =2 /_APB,` use this to find `/_AOB` as `/_ AOB =360^(@) - 2 /_ APB` (iv)` /_AOB = /_ COD`

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