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In the above figure (not to scale), E and F are the mid points of AB and CD respectively. `bar(AB) | |bar(CD),bar(BC)||bar(AD),/_ADE =70^(@)`, AND `/_BCE =40^(@), /_DEC` isA. `70^(@)`B. `40^(@)`C. `110^(@)`D. `120^(@)` |
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Answer» Correct Answer - c (i) Join E and F . Alternate angles are equal. (ii) Draw a line parallel to `bar(AD)` and `bar (BC)` through E and F. (iii) Find angles CEF and DEF using alternate angles property . (iv) The sum of above is `/_ DEC`. |
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