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In the above figure, `bar(AF) || bar(ED),bar(CG) ||bar(AB)` and `bar(AE) ||bar(HD)` If `/_ FPD =40^(@)`, then `/_ AED =`A. `40^(@)`B. `80^(@)`C. `120^(@)`D. `140^(@)` |
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Answer» Correct Answer - D (i) `(/_FPD` and `/_PDE` are alternate angles and are equal. (ii) `/_ PDE` and `/_ AED` are interior angles on the same side of transversal and their sum is `180^(@)`. |
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