In specific condition of N/50 KCL of solution is .002765mho cm calcula

1.	In specific condition of N/50 KCL of solution is .002765mho cm calculaye the equivalent conductance
Answer» Answer: EQUIVALENT CONDUCTANCE = K(kappa)×1000/N = 0.002765×1000/(1/50) = 2.765×50 MHO cm^2 /gequivalent

In specific condition of N/50 KCL of solution is .002765mho cm calculaye the equivalent conductance

Answer»

Answer:

EQUIVALENT CONDUCTANCE = K(kappa)×1000/N

= 0.002765×1000/(1/50)

= 2.765×50 MHO cm^2 /gequivalent