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In series with `20 ohm` resitor a `5` henry inductor is placed. To the combination an e.m.f. of `5` volt is applied. What will be the rate of increase of current at `t=0.25 sec`?A. `e`B. `e^(-2)`C. `e^(-1)`D. none of these |
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Answer» Correct Answer - C `i=i_(0)(1e^(-Rt//L))implies(di)/(dt)=i_(0)((R )/(L))e^(-Rt//L)=(E)/(L)e^(-Rt//L)` |
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