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In `Se(Z = 34)` how many electrons are present with `m_(l) = 2` ?A. `20`B. `4`C. `2`D. None of these |
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Answer» Correct Answer - C In `Se(Z= 34)` how many electrons ……………. `_(34)Se = [Ar]3d^(10), 4s^(2)p^(4)` |
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