In ∆ RST, line PQ || side ST, R-P-S and R-Q-T, RP = 4, PS = 6, RQ =

1.	In ∆ RST, line PQ \|\| side ST, R-P-S and R-Q-T, RP = 4, PS = 6, RQ = 3. Find QT.
Answer» $\textbf{Given:}$ $\text{In $\<klux>TRIANGLE</klux>$RST, PQ$\parallel$ST, RP=4, PS=6, RQ=3}$ $\textbf{To find:}$ $\text{Length of QT}$ $\textbf{Solution:}$ $\textbf{Basic proportionality theorem(Thales theorem):}$ $\text{If a line is drawn parallel to one side of a}$ $\text{triangle then it cuts other two sides proportionally.}$ $\text{In $\triangle$RST, by Thales theorem}$ $\dfrac{RP}{PS}=\dfrac{RQ}{QT}$ $\dfrac{4}{6}=\dfrac{3}{QT}$ $\dfrac{2}{3}=\dfrac{3}{QT}$ $\implies\,QT=\dfrac{9}{2}$ $\implies\bf\,QT=4.5\,text{cm}$ Find more: In a triangle abc x is the MIDPOINT of ac and XY parallel to AB prove y is midpoint brainly.in/question/8514294# Given DE parallel to BC AD=4.5 BD=9cm EC=8cm what is length of AE brainly.in/question/13821241 In triangle abc;de\|\|ab;ad=7cm;cd=5cm and bc=18cm find be;ce brainly.in/question/12249976