In right angled ∆LMN, ∠LMN = 90°, ∠L = 50° and ∠N = 40°. Wr

1.	In right angled ∆LMN, ∠LMN = 90°, ∠L = 50° and ∠N = 40°. Write the following ratios.i. sin 50° ii. cos 50°aiii. tan 40°iv. cos 40°
Answer» i. sin 50° = \(\cfrac{Opposite \,side \,of \,50°}{Hypotenuse}\) = \(\frac{MN}{LN}\) ii.cos 50° = \(\cfrac{Adjacent \,side \,of \,50°}{Hypotenuse}\) = \(\frac{LM}{LN}\) iii. tan 40° = \(\cfrac{Opposite\,side \,of \,40°}{Adjacent\,side\, of \,40°}\) = \(\frac{LM}{MN}\) iv. cos 40° = \(\cfrac{Adjacent \,side \,of \,40°}{Hypotenuse}\) = \(\frac{MN}{LN}\)

In right angled ∆LMN, ∠LMN = 90°, ∠L = 50° and ∠N = 40°. Write the following ratios.i. sin 50° ii. cos 50°aiii. tan 40°iv. cos 40°

Answer»

i. sin 50° = \(\cfrac{Opposite \,side \,of \,50°}{Hypotenuse}\) = \(\frac{MN}{LN}\)

ii.cos 50° = \(\cfrac{Adjacent \,side \,of \,50°}{Hypotenuse}\) = \(\frac{LM}{LN}\)

iii. tan 40° = \(\cfrac{Opposite\,side \,of \,40°}{Adjacent\,side\, of \,40°}\) = \(\frac{LM}{MN}\)

iv. cos 40° = \(\cfrac{Adjacent \,side \,of \,40°}{Hypotenuse}\) = \(\frac{MN}{LN}\)