In right angled ΔDEF, ∠E = 90° , DE = 5 cm, EF = 12 cm, DF = 13 cm

1.	In right angled ΔDEF, ∠E = 90° , DE = 5 cm, EF = 12 cm, DF = 13 cm. Find the radius of incircle.1. 1 cm2. 2 cm3. 3 cm4. 4 cm
Answer» Correct Answer - Option 2 : 2 cm Given: DEF is a right triangle. ∠E = 90° DE = 5 cm EF = 12 cm DF = 13 cm Formula used: Radius of incircle = area of triangle/semi perimeter of triangle Calculation: Radius of incircle = [(1/2) × 12 × 5]/ [(13 + 12 + 5)/2] ⇒ 2 cm ∴ The radius of incircle is 2 cm

In right angled ΔDEF, ∠E = 90° , DE = 5 cm, EF = 12 cm, DF = 13 cm. Find the radius of incircle.1. 1 cm2. 2 cm3. 3 cm4. 4 cm

Answer» Correct Answer - Option 2 : 2 cm

Given:

DEF is a right triangle.

∠E = 90°

DE = 5 cm

EF = 12 cm

DF = 13 cm

Formula used:

Radius of incircle = area of triangle/semi perimeter of triangle

Calculation:

Radius of incircle = [(1/2) × 12 × 5]/ [(13 + 12 + 5)/2]

⇒ 2 cm

∴ The radius of incircle is 2 cm

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In right angled ΔDEF, ∠E = 90° , DE = 5 cm, EF = 12 cm, DF = 13 cm. Find the radius of incircle.1. 1 cm2. 2 cm3. 3 cm4. 4 cm

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