In right angle triangle ABC and BCD, AB/CD=1/2 then A(∆ABC)/A(∆BCD

1.	In right angle triangle ABC and BCD, AB/CD=1/2 then A(∆ABC)/A(∆BCD) = ?
Answer» Answer: if the heights of two traingles are equal then the area of the triangles are PROPORTIONAL to its base Step-by-step explanation: so , RATIO of Area of TRAINGLE ABC and TRIANGLE BCD =1/2

In right angle triangle ABC and BCD, AB/CD=1/2 then A(∆ABC)/A(∆BCD) = ?

Answer»

Answer:

if the heights of two traingles are equal

then the area of the triangles are PROPORTIONAL to its base

Step-by-step explanation:

so ,

RATIO of Area of TRAINGLE ABC and TRIANGLE BCD

=1/2

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In right angle triangle ABC and BCD, AB/CD=1/2 then A(∆ABC)/A(∆BCD) = ?​

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In right angle triangle ABC and BCD, AB/CD=1/2 then A(∆ABC)/A(∆BCD) = ?