In rhombus PQRS ∆P+∆Q+∆R+∆S =

1.	In rhombus PQRS ∆P+∆Q+∆R+∆S =
Answer» align="absmiddle" alt="\huge\mathfrak\red {Answer:}" CLASS="latex-formula" id="TexFormula1" src="https://tex.z-dn.net/?f=%5Chuge%5Cmathfrak%5Cred%20%7BAnswer%3A%7D" title="\huge\mathfrak\red {Answer:}"> All angles of a quadrilateral ADD up to 360° Rhombus is a quadrilateral. Therefore the answer is 360° $\mathfrak\purple {Hope\: this\: helps\: you...}$ $\mathfrak\green {Hope\: you\: have\: a\:nice\:day\:ahead...}$

Answer»

align="absmiddle" alt="\huge\mathfrak\red {Answer:}" CLASS="latex-formula" id="TexFormula1" src="https://tex.z-dn.net/?f=%5Chuge%5Cmathfrak%5Cred%20%7BAnswer%3A%7D" title="\huge\mathfrak\red {Answer:}">

All angles of a quadrilateral ADD up to 360°

Rhombus is a quadrilateral.

Therefore the answer is

360°

$\mathfrak\purple {Hope\: this\: helps\: you...}$

$\mathfrak\green {Hope\: you\: have\: a\:nice\:day\:ahead...}$

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In rhombus PQRS ∆P+∆Q+∆R+∆S =​

360°

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In rhombus PQRS ∆P+∆Q+∆R+∆S =