Related InterviewSolutions

• Given below are some triangles and lengths of line segments. Identify in which figures, ray PM is the bisector of `/_QPR`.
• In the figure, `PS=3`, `SQ=6`, `QR=5`, `PT=x` and `TR=y`. Give any two pairs of values of `x` and `y` such that line `ST||` side `QR`.
• As shown in the adjoining figure, two poles of height 8 m and 4 m are perpendicular to the ground. If the length of shadow of smaller pole due to sunlight is 6 m, then how long will be the shadow of the bigger pole at the same time?
• `DeltaLMN~DeltaPQR`, `9xxA(DeltaPQR)=16xxA(DeltaLMN)`. If `QR=20`, then find `MN`.
• As shown in the figures, two poles of height 8m and 4m are perpendicular to the groudn. If the length of shadow smaller pole due to sunlight is 6 m then long will be the shadow of the bigger pole of the same time?
• In the adjoining figure, `BP bot AC`, `CQ bot AB`, `A-P-C`, `A-Q-B`. Complete the following activity to Prove `DeltaAPB~DeltaAQC`. In `DeltaAPB` and `DeltaAQC` `/_APB=square^(@)`…….`(1)` `/_AQC=square^(@)`……..`(2)` `:./_APB~=/_AQC`…....(`square`) `:.DeltaAPB~DeltaAQC`......(`square`)
• In `DeltaMNP, NQ` is a bisector of `/_N`. If `MN=5, PN=7, MQ=2.5,` the find QP.
• In the figure seg `PQ||` seg DE, `A(DeltaPQF)=20` units `PF=2DP`,then find `A(square DPQE)` by completing the following activity: Activity: `A(DeltaPQF)=20` sq units, `PF=2DP`. Let us assume `DP=x` `:.PF=2x` `DF=DE+square=square+square=3x` In `DeltaFDE` and `DeltaFPQ`. `/_FDE~=/_square` ..........(Corresponding angles) `/_FED~=/_square` .....(Corresponding angles) `:.DeltaFDE~DeltaFPQ` .....(AA test) `:.(A(DeltaFDE))/(A(DeltaFPQ))=(square)/(square)=((3x)^(2))/((2x)^(2))=9/4` `A(DeltaFDE)=9/4A(DeltaFPQ)=9/4xxsquare=square` `A(squareDPQE)=A(DeltaFDE)-A(DeltaFPQ)` `=square-square` `=square`
• In figure `XY||` seg AC. If `2AX=3BX` and `XY=9`, complete the activity to find the value of AC. Activity: `2AX=3BX` `:.(AX)/(BX)=(square)/(square)` `:.(AX+BX)/(BX)=(square+square)/(square)`.........(By componendo) `:.(AB)/(BX)=(square)/(square)`.............1`DeltaBCA~DeltaBYX`.......(`square` test of similarity) `:.(BA)/(BX)=(AC)/(XY)` ..............(Corresponding sides of similar triangles) `:.(square)/(square)=(AC)/9` `:.AC=square` ...........[From 1]
• In the adjoining figure, seg `XY||` seg `AC`, IF `3AX=2BX` and `XY=9` then find the length of `AC`.