1.

in ∆PQR angle Q is 90 degree and PQ=4cm and PR=9cm. Find :- sin P, tan R, sin R+cos R. I will mark the correct answer the brainliest​

Answer»

ANSWER:

QR=√65

sinP=QR/PR= √65/9

tanR=PQ/QR=4/√65

sinR+cosR = (PQ+QR)/PR = (4+√65)/9



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