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in ∆PQR angle Q is 90 degree and PQ=4cm and PR=9cm. Find :- sin P, tan R, sin R+cos R. I will mark the correct answer the brainliest |
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Answer» QR=√65 tanR=PQ/QR=4/√65 sinR+cosR = (PQ+QR)/PR = (4+√65)/9 |
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