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In one litre of 3M solution of NaOH, `H_(2)SO_(4)` is added until `27.4 Kcal` energy us released. Then 2 moles of `CH_(3)COOH` is added to the resulting solution and the final volume becomes 2 litre. If x moles of AgCN can be dissolved in the final solution, what is `x xx 10^(4)`? `H^(+)+OH^(-)rarrH_(2)O " "DeltaH=-13.7Kcal//mol` `K_(sp)AgCN=10^(-12)K_(a)(CH_(3)COOH)=10^(-5) K_(a)(HCN)=10^(-9)` |
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Answer» Correct Answer - 2 `pH` of the `2` litre solution `= pK_(a) "of" CH_(3)COOH=5` `AgCNhArr Aunderset(s)(g^(+))+Cunderset(s)(N)^(-)` `CN^(-)+underset(10^(-5))H^(+)rarrHunderset(s)CN` `(S^(2))/(10^(-5)xx10^(-12))=10^(9)` `s=10^(-4)m/L` |
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