In △OAB, if −−→OA=→a,−−→OB=→b,L is mid point of −� – InterviewSolution

1.	In △OAB, if −−→OA=→a,−−→OB=→b,L is mid point of −−→OA and M is a point on −−→OB such that −−→OM:−−→MB=2:1. If P is the mid point of −−→LM, then −−→AP=
Answer» In $△ O A B,$ if $- - \to O A = \to a, - - \to O B = \to b, L$ is mid point of $- - \to O A$ and $M$ is a point on $- - \to O B$ such that $- - \to O M : - - \to M B = 2 : 1.$ If $P$ is the mid point of $- - \to L M,$ then $- - \to A P =$

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