1.

In new temperature scale W, freezing point of water is 39^(@)W and boiling point is 239^(@)W. What would be the temperature on new temperature scale for 39^(@)C temperature ?

Answer»

`200^(@)W`
`139^(@)W`
`78^(@)W`
`117^(@)W`

SOLUTION :`(""^(@)C-0)/(100-0)=(W^(@)-39)/(239-39)`
`(39)/(100)=(W-39)/(200)`
`2xx39+39=W`
`:.W=39xx(200)/(100)+39`
`=39xx2+39`
`=78+39`
`=117^(@)W`


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