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In N3H, oxidation number of N atoms are :-O -1,0,0O -1/3,-1/3,-1/3O -3, -3, -3O -1,-1,0 |
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Answer» OXIDATION number of H atom = +1 oxidation number of N atom = x sum of oxidation number of all ATOMS = 0 oxidation number of H + 3 × oxidation number of N = 0 1 + 3x = 0 x = - 1/3 |
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