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In maxwell's speed distribution curve, for N_(2 ) gas, the average of |relative velocity| between two molecules at 300 k will be : - |
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Answer» 300 m/sec  `|V_("rel")|=sqrt(V^(2)+V^(2)-2(V)(V) cos theta)=2 V|"sin" (theta)/(2)|` `langle V_("rel") RANGLE=(overset(pi)underset(0)INT 2V1|"sin"(theta)/(2)|d theta)/(overset(pi)underset(0)int d theta)=(4V)/(pi)` `langle V_("rel") rangle =(4)/(pi) V_("AVERAGE")=(4)/(pi) sqrt((8RT)/(pi m_(0))) =(4)/(pi) sqrt((8xx8.3 xx 300)/(3.14 xx 28 xx 10^(-3))) =606` m/sec |
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