1.

In Leibig’s method. 0.24 g of organic compound on combustion with dry oxygen produced of 0.62 g of CO2 and 0.11 g of H2O. Determine the percentage composition of the compound.

Answer»

Mass of organic compound = m = 0.24 g 

Mass of carbon dioxide formed = 0.62 g 

Mass of water formed = 0.11 g

Percentage of carbon = 12/4 x 0.62/0.24 x 100 = 70.45

Percentage of hydrogen = 2/4 x 0.11/0.24 x 100 = 5.09

Percentage of oxygen = [100 – (70.5 + 5.0)] = 24.46



Discussion

No Comment Found

Related InterviewSolutions