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In Leibig’s method. 0.24 g of organic compound on combustion with dry oxygen produced of 0.62 g of CO2 and 0.11 g of H2O. Determine the percentage composition of the compound. |
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Answer» Mass of organic compound = m = 0.24 g Mass of carbon dioxide formed = 0.62 g Mass of water formed = 0.11 g Percentage of carbon = 12/4 x 0.62/0.24 x 100 = 70.45 Percentage of hydrogen = 2/4 x 0.11/0.24 x 100 = 5.09 Percentage of oxygen = [100 – (70.5 + 5.0)] = 24.46 |
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