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In LCR series circuit an ac emf of 2 volt and frequency 50 Hz is applied across the combination. If resistance is `4Omega`, capacitance is `8muF` and inductance is `10^(-2)H` then the voltage across inductor will beA. (3/5 V)B. (5/3 V)C. (2/3 V)D. (0.02 V) |
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Answer» Correct Answer - D `I=(e)/(Z)` `X_(L)=2pifL` `=2xx3.14xx50xx10^(-2)=3.14Omega` `X_(C)=(1)/(2pifC)=(1)/(2xx3.14xx50xx8xx10^(-6))` `=(0.3185xx10^(4))/(8)=(3185)/(8)=397Omega` `Z=sqrt(R^(2)(X_(L)-X_(C))^(2))` `Z=397Omega` `e_(R)=I*R=(e)/(Z)*R` `=(2)/(397)xx4=0.02V`. |
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