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in in a circle of diameter 40 cm the length of a chord is 20 cm find the length of minor arc of the chord. please answer in deatail |
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Answer» Step-by-step explanation: in question given diameter = 40 cm radius = D/2 = 40/2 = 20cm. the LENGTH of a chord is 20cm. a/q ∆ OAB is EQUILATERAL traingle. θ = 60° l = 20 × 60° × π / 180° l = 20π / 3cm thus, the length of the minor arc of the chord 20π / 3cm |
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