1.

in in a circle of diameter 40 cm the length of a chord is 20 cm find the length of minor arc of the chord. please answer in deatail​

Answer»

ANSWER:

Step-by-step explanation:

in question given

diameter = 40 cm

radius = D/2

= 40/2

= 20cm.

the LENGTH of a chord is 20cm.

a/q

∆ OAB is EQUILATERAL traingle.

θ = 60°

l = 20 × 60° × π / 180°

l = 20π / 3cm

thus,

the length of the minor arc of the chord

20π / 3cm



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