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In IABC, AB-AC and the bisectors of LB and LC meet at a point O. Prove that BO*CO and the ray Ao is the bisector8 |
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Answer» since AB=BCso <B=<C (angles opposite to equal sides)so <OBC=<OCBso BO=OC (sides opposite to equal angles)since BO=OC so <BAO=<OACso AO is bisector of <A |
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