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In hydrogen atom, if the difference in the energy of the electron in n=2 and n=3 orbits is E., then ionization energy of hydrogen atom is 3.6n E. The value of n is (integer only)

Answer» In hydrogen atom, if the difference in the energy of the electron in n=2 and n=3 orbits is E., then ionization energy of hydrogen atom is 3.6n E. The value of n is (integer only)


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