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*In how many years Rs. 6000 will amount to Rs 7986 at a compound interest rate of 10 %?*1️⃣ 22️⃣ 33️⃣ 44️⃣ 5 |
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Answer» Answer: After 3 YEARS the principal of 6000 amount to 7986 .Let after t years the principal of 6000 amount to 7986. Principal = 6000 RATE of interest= 10%=0.1 Amount= 7986 The formula for amount is A=P(1+r)^tA=P(1+r) t
where, P is principal, r is interest rate and t is time in years. 7986=6000(1+0.1)^t7986=6000(1+0.1) t
\frac{7986}{6000}=(1.1)^t 6000 7986
=(1.1) t
\frac{1331}{1000}=(\frac{11}{10})^t 1000 1331
=( 10 11
) t
(\frac{11}{10})^3=(\frac{11}{10})^t( 10 11
) 3 =( 10 11
) t
On comparing both sides, we get t=3t=3 Let after t years the principal of 6000 amount to 7986. Principal = 6000 Rate of interest= 10%=0.1 Amount= 7986 The formula for amount is A=P(1+r)^tA=P(1+r) t
where, P is principal, r is interest rate and t is time in years. 7986=6000(1+0.1)^t7986=6000(1+0.1) t
\frac{7986}{6000}=(1.1)^t 6000 7986
=(1.1) t
\frac{1331}{1000}=(\frac{11}{10})^t 1000 1331
=( 10 11
) t
(\frac{11}{10})^3=(\frac{11}{10})^t( 10 11
) 3 =( 10 11
) t
On comparing both sides, we get t=3t=3 |
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