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In how many ways can a team of 11 players be selected from 14 players when two of them play as goalkeepers only?(a) 112 (b) 132 (c) 91 (d) 182 |
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Answer» (b) 132 As each team of 11 players has one goalkeeper and 10 team members, and out of 14 players there are 2 goalkeepers and 12 team members. So the number of ways in which a team of 11 can be selected = 12C10 x 2C1 \(\frac{12!}{10!\times2!}\times2\) = \(\frac{12\times11}{2}\times2\) = 132. |
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