1.

In how many ways can 10 identical presents be distributed among 6 children so that each child gets at least one present?

Answer»

No of identical presents = 10
no of CHILDREN's to be distributed = 6
no of ways by which presents can be distributed = nPr = N!/(n-R)! × r!
= 10!/ (10-6)!×6!
=(10×9×8×7×6!)/4! × 6!
= (10×9×8×7)/(4×3×2)
= 10×3×7
=210


Discussion

No Comment Found

Related InterviewSolutions