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In how many ways 6 books out of 10 different books can be arranged in a book-self so that 3 particular books are always togetherPlease explain the answer to this sum |
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Answer» Answer: 10080 Step-by-step explanation: CONSIDERING 3 books as together as 1 4 books are arrangef AMONG 8 BOKS in 8p4 ways =1680 now the 3 books are arranged among themselves in 3 FACTORIAL ways =6 total nos of ways =1680×6=10080 ways |
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