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In growth pattern'(1-n/k) is |
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Answer» Answer: i think this is a logistic GROWTH equation Explanation: A population of Spotted Fritillary butterflies EXHIBITS logistic growth. If the carrying capacity is 500 butterflies and r = 0.1 individuals/(individuals x MONTH), what is the maximum population growth RATE for the population? (Hint: maximum population growth rate occurs when N = K/2). In the question you're given the following information: K = 500 r = 0.1 Max. pop growth at K/2 Therefore, Max. population size = K/2 = 500/2 = 250 dN/dt = RN[1-N/K] - this is the logistic growth equation dN/dt = (0.1)(250) [1 - (250)/500)] dN/dt = 12.5 individuals/month |
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