In given figure. ST-RQ. PS-3 cm and SR-4 cm. Find the ratio of the arP

1.	In given figure. ST-RQ. PS-3 cm and SR-4 cm. Find the ratio of the arPST to the area of Î PRQ.P 3cm S ëcm
Answer» Given: ST \|\| RQ PS= 3 cm SR = 4cm We know that the ratio of areas of two similar triangles is equal to the ratio of squares of their corresponding sides. ar(∆PST) /ar(∆PRQ)= (PS)²/(PR)² ar(∆PST) /ar(∆PRQ)= 3²/(PS+SR)² ar(∆PST) /ar(∆PRQ)= 9/(3+4)²= 9/7²=9/49 Hence, the required ratio ar(∆PST) :ar(∆PRQ)= 9:49

In given figure. ST-RQ. PS-3 cm and SR-4 cm. Find the ratio of the arPST to the area of Î PRQ.P 3cm S ëcm

Answer»

Given:

ST || RQ

PS= 3 cm

SR = 4cm

We know that the ratio of areas of two similar triangles is equal to the ratio of squares of their corresponding sides.

ar(∆PST) /ar(∆PRQ)= (PS)²/(PR)²

ar(∆PST) /ar(∆PRQ)= 3²/(PS+SR)²

ar(∆PST) /ar(∆PRQ)= 9/(3+4)²= 9/7²=9/49

Hence, the required ratio ar(∆PST) :ar(∆PRQ)= 9:49