In given figure, a light ray AB is incident normally on one face PQ of

1.	In given figure, a light ray AB is incident normally on one face PQ of an equilateral glass prism. Find out the angles at faces PQ and PR. A. 60° B. 30° C. 45° D. 90°
Answer» Angle of incidence, i = 0° Angle of refraction, r = sin (i)×n Where n = refractive index So, r₁ = 0° Where, r₁ = angle of refraction at PQ r₂ = angle of incidence from inside on side PR A = angle of prism We know that A = r₁ + r₂ r₂ = A – r₁ = 60° – 0° = 60°

In given figure, a light ray AB is incident normally on one face PQ of an equilateral glass prism. Find out the angles at faces PQ and PR. A. 60° B. 30° C. 45° D. 90°

Answer»

Angle of incidence, i = 0°

Angle of refraction, r = sin (i)×n

Where n = refractive index

So, r₁ = 0°

Where,

r₁ = angle of refraction at PQ

r₂ = angle of incidence from inside on side PR

A = angle of prism

We know that

A = r₁ + r₂

r₂ = A – r₁

= 60° – 0°

= 60°