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In give fig ab||cd the value of x is |
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Answer» ong>Answer: LET A1, A2, A3, A4, and A5 be five numbers between 8 and 26 such that 8, A1, A2, A3, A4, A5, 26 is an A.P. Here, a = 8, b = 26, n = 7 Therefore, 26 = 8 + (7 – 1) d ⇒ 6d = 26 – 8 = 18 ⇒ d = 3 A1 = a + d = 8 + 3 = 11 A2 = a + 2d = 8 + 2 × 3 = 8 + 6 = 14 A3 = a + 3D = 8 + 3 × 3 = 8 + 9 = 17 A4 = a + 4d = 8 + 4 × 3 = 8 + 12 = 20 A5 = a + 5d = 8 + 5 × 3 = 8 + 15 = 23 Thus, the required five numbers between 8 and 26 are 11, 14, 17, 20, and 23. |
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