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IN Four identical metal plates, Plates 1 and 4 are connected by a connecting wire. A battery of emf V volts is connected between plates 2 and 3. The electric field between plates 3 and 4 is 2V/Kd. Find the value of K.

Answer»

acitance increases as the DIELECTRIC constant K>1. (ii) POTENTIAL difference V= CQ . As C increases and Q remains the same since the battery is disconnected, the p.d. between the plates decreases.(iii) Electric field E= dV where V is the p.d. and d the separation between the plates. As V decreases and d remains the same, electric field also decreases.(iv) Energy stored in a CAPACITOR U= 21 CQ 2 . As Q is constant and C increases, U decreases.



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