In figure, the optical fiber is l = 2m long and has a diameter of d =

1.	In figure, the optical fiber is l = 2m long and has a diameter of d = 20 μ m. If a ray of light is incident on one end of the fiber at angleθ₁ = 40º , the number of reflection it makes before emerging from the other end is close to: (A) 57000 (B) 45000(C) 66000 (D) 55000
Answer» The number of reflection it makes before emerging from the other END is close to: (A) 57000 This can be calculated as FOLLOWS: Given, l = 2M and θ₁ = 40º THUS, As per the question, l sin 40º = 1.31 sin θ sin θ = 0.64 / 1.31 ≈ 1/2 ∴ θ = 30º Now, a = D / ( 1 / √3 ) = 20√3 x 10⁻⁶ m Thus, number of reflections = 20 / (20√3 x 10⁻⁶) ≈ 57000

In figure, the optical fiber is l = 2m long and has a diameter of d = 20 μ m. If a ray of light is incident on one end of the fiber at angleθ₁ = 40º , the number of reflection it makes before emerging from the other end is close to: (A) 57000 (B) 45000(C) 66000 (D) 55000

Answer»

The number of reflection it makes before emerging from the other END is close to:

(A) 57000

This can be calculated as FOLLOWS:

Given, l = 2M and θ₁ = 40º

THUS, As per the question,

l sin 40º = 1.31 sin θ

sin θ = 0.64 / 1.31

≈ 1/2

∴ θ = 30º

Now, a = D / ( 1 / √3 )

= 20√3 x 10⁻⁶ m

Thus, number of reflections = 20 / (20√3 x 10⁻⁶)

≈ 57000

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In figure, the optical fiber is l = 2m long and has a diameter of d = 20 μ m. If a ray of light is incident on one end of the fiber at angleθ₁ = 40º , the number of reflection it makes before emerging from the other end is close to: (A) 57000 (B) 45000(C) 66000 (D) 55000

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