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In figure, T is a point on side QR of ∆PQR and S is a point such that RT = ST. Prove that PQ + PR > QS |
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Answer» In ∆PQR we have PQ + PR > QR ⇒ PQ + PR > QT + TR ⇒ PQ + PR > QT + ST ∴RT = ST In ∆QST QT + ST > SQ ∴ PQ + PR > SQ |
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