1.

In figure PQ||RS,PAB=79,ACS=100. determine ABC, BAC,CAQ​

Answer»

ANSWER:

ANSWER

Given

PQ∥RS

∠PAB=70

0

∠ACS=110

0

∠BAC=?

∠BCS=180−110=70

0

(STRAIGHT LINE)

∠DAB=∠ABC=70

0

(alternate angle)

Now from △ABC

By angle sum property

∠BAC+70+70=180

0

∠BAC=40

0



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