1.

In figure, OA OD, OC OB, OD = OA and OC = OB. Prove that AB = CD​

Answer»

GIVEN:

\sf{\angle DOA = \angle BOC = 90°}

\sf{OD = OA}

\sf{OC = OB}

Proof:

Let \sf{\angle AOC = x}

From ∆DOC and ∆AOB,

\sf{•\:\angle DOC = \angle AOB = 90° + x}

\sf{•\:OD = OA}

\sf{•\:OC = OB}

By SAS CONGRUENCY,

\bold{∆DOC \cong ∆AOB}

By corresponding parts of congruent TRIANGLES (CPCT),

\bold{\red{AB=CD}}

HENCE proved



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