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In figure, ∠DAB = 60°, ∠ABD = 50°, then ∠ACB equal(a) 60°(b) 50°(c) 70°(d) 80° |
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Answer» Answer is (c) 70° ∠DAB = 60° and ∠ADB = 50° In ΔADB ∠DAB + ∠ABD + ∠ADB = 180° ⇒ 60° + 50° + ∠ADB = 180° ⇒ ∠ADB = 180° – (60° – 50°) ⇒ ∠ADB = 70° ∠ACB and ∠ADB are angles in same segment. So will be equal ⇒ ∠ACB = ∠ADB = 70° |
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