1.

In figure, ∠DAB = 60°, ∠ABD = 50°, then ∠ACB equal(a) 60°(b) 50°(c) 70°(d) 80°

Answer»

Answer is (c) 70°

∠DAB = 60° and ∠ADB = 50°

In ΔADB

∠DAB + ∠ABD + ∠ADB = 180°

⇒ 60° + 50° + ∠ADB = 180°

⇒ ∠ADB = 180° – (60° – 50°)

⇒ ∠ADB = 70°

∠ACB and ∠ADB are angles in same segment.

So will be equal

⇒ ∠ACB = ∠ADB

= 70°



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