in figure, < BZ A meets BC at D. Find Z ADB and Z ADc2355°, < C45° a – InterviewSolution

1.	in figure, < BZ A meets BC at D. Find Z ADB and Z ADc2355°, < C45° and the bisectory:△55°452
Answer» B=55 and C=45 now A+B+C=180so A=80 now AD is a bisectorso ADB=ADC=A/2=80/2=40

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