1.

In figure, ∠BAC will be :(A) 80°(B) 160°(C) 90°(D) 200°

Answer»

Answer is (A) 80°

We know that sum of angles at center is 360°.

∠BOC – ∠BOA + ∠COA = 360°

⇒ ∠BOC + 85° + 115° = 360°

⇒ ∠BOC + 200° = 360°

∴ ∠BOC = 360° – 200° = 160°

Angle subtended at center of a circle is double the angle at remaining part by same arc.

∠BOC = 2∠BAC

⇒ ∠BOC = \(\frac { \angle BOC }{ 2 } \) = \(\frac { { 160 }^{ \circ } }{ 2 } \)

∴ ∠BAC = 80°



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