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In figure, ∠BAC will be :(A) 80°(B) 160°(C) 90°(D) 200° |
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Answer» Answer is (A) 80° We know that sum of angles at center is 360°. ∠BOC – ∠BOA + ∠COA = 360° ⇒ ∠BOC + 85° + 115° = 360° ⇒ ∠BOC + 200° = 360° ∴ ∠BOC = 360° – 200° = 160° Angle subtended at center of a circle is double the angle at remaining part by same arc. ∠BOC = 2∠BAC ⇒ ∠BOC = \(\frac { \angle BOC }{ 2 } \) = \(\frac { { 160 }^{ \circ } }{ 2 } \) ∴ ∠BAC = 80° |
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