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In figure ABC is an isosceles triangle in which AB = AC. CP || AB and AP is the bisector of exterior ∠CAD of △ABC. Prove that ∠PAC=∠BCA and ABCP is a parallelogram.

Answer» In figure ABC is an isosceles triangle in which AB = AC. CP || AB and AP is the bisector of exterior CAD of ABC. Prove that PAC=BCA and ABCP is a parallelogram.




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